SQL生成数据字典语句
时 间:2019-08-02 08:31:16
作 者:缪炜 ID:24010 城市:江阴
摘 要:SQL生成数据字典语句
正 文:
Select [表名] = c.name, [表说明] = Isnull(f.[value],''), [列名] = a.name, [列序号] = a.column_id, [标识] = CASE WHEN is_identity = 1 THEN '√' ELSE '' END, [主键] = CASE WHEN EXISTS (Select 1 FROM sys.objects x JOIN sys.indexes y ON x.TYPE = N'PK' AND x.name = y.name JOIN sysindexkeys z ON z.id = a.object_id AND z.indid = y.index_id AND z.colid = a.column_id) THEN '√' ELSE '' END, [类型] = b.name, [字节数] = CASE WHEN a.[max_length] = -1 AND b.name != 'xml' THEN 'max/2G' WHEN b.name = 'xml' THEN '2^31-1字节/2G' ELSE Rtrim(a.[max_length]) END, [长度] = CASE WHEN Columnproperty(a.object_id,a.name,'Precision') = -1 THEN '2^31-1' ELSE Rtrim(Columnproperty(a.object_id,a.name,'Precision')) END, [小数] = Isnull(Columnproperty(a.object_id,a.name,'Scale'), 0), [是否为空] = CASE WHEN a.is_nullable = 1 THEN '√' ELSE '' END, [列说明] = Isnull(e.[value],''), [默认值] = Isnull(d.text,'') FROM sys.columns a LEFT JOIN sys.types b ON a.user_type_id = b.user_type_id INNER JOIN sys.objects c ON a.object_id = c.object_id AND c.TYPE = 'U' LEFT JOIN syscomments d ON a.default_object_id = d.id LEFT JOIN sys.extended_properties e ON e.major_id = c.object_id AND e.minor_id = a.column_id AND e.class = 1 LEFT JOIN sys.extended_properties f ON f.major_id = c.object_id AND f.minor_id = 0 AND f.class = 1 orDER BY c.name
Access软件网QQ交流群 (群号:54525238) Access源码网店
常见问答:
技术分类:
源码示例
- 【源码QQ群号19834647...(12.17)
- 【Access选项卡示例】Ac...(09.09)
- 【Access源码示例】按输入...(09.02)
- 【Access日期区间段查询】...(08.29)
- 【Access日期区间段查询】...(08.27)
- Access怎样才能实现日期时...(08.21)
- 【Access定时打开查询】A...(08.19)
- Access生成固定数量的记录...(08.13)
- Access怎样才能实现日期时...(08.12)
- Access利用导航窗体控件对...(08.03)
学习心得
最新文章
- Access表中的字段名、字段标题...(09.19)
- Access快速开发平台--更改“...(09.18)
- 【中秋及国庆优惠】Access培训...(09.15)
- Access如何将日期型的数值转换...(09.14)
- 英文输入法输入数据中存在单引号引起...(09.11)
- 【Access选项卡示例】Acce...(09.09)
- 让Access光标停留在指定的控件...(09.07)
- 关于Access查询条件里使用通配...(09.06)
- Access报表偷懒制作法--Ac...(09.05)
- Access快速开发平台--窗体数...(09.04)